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<< Click to show the Table of Contents >> ASP: EXAMPLE 3. COMBINATION OF SEVERAL LAYERS WITH DIFFERENT WEIGHTS |
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A scenario similar to example 1 and example 2 is presented, with 3 transmitters and the same coverage, with the same group of 7 points (purple), but with another group of 5 points (green), where the calculation magnitude is units of the point layer, with one unit at each point, the weight is equal to 1 for the purple group and 2 for the green group, the minimum is equal to 0 for both, the maximum is equal to 3 for the purple group and 2 for the green group, and the saturation is defined as 4 for the purple group and 3 for the green group.
The process in this scenario would be as described below.
ITERATION 1 Step 1: Analyze coverage Target coverage: Purple points A, B, C, D, E, F, G and green points A, B, C, D, E (12 units). Tx1 coverage: Purple points A, B, C, D, E and green points A, B (7 units). Tx2 coverage: Purple points E, F and green points C, D (5 units). Tx3 coverage: Purple points A, B, F, G and green points A, B, E (9 units). Step 2: Score and choose the prioritized transmitter Factors that may modify the score: •The weight of the layer for units is 1 for the purple group and 2 for the green group, so the green group's scores will be multiplied by 2. •By default, the multipliers are set to 1 and the additions to 0, so the scores do not change. •By default, there are no transmitters with manually set priority or marked as "always prioritize", so the scores do not change. Following the same process as in the previous examples, the scores are calculated with the purple and green points separately, modified according to these factors, added together, and the one with the highest score is the chosen transmitter. Considering that the score in case of saturation will be 0.001, in the first iteration it would be: P(Tx1) = 0.001 + 2/2*2 = 2.001 P(Tx2) = 2/3 + 0.001*2 = 0.669 P(Tx3) = 0.001 + 0.001*2 = 0.003 Tx1 is chosen because it has the highest score. Step 3: Remove coverage provided by the chosen transmitter from the target coverage Since Tx1 covered purple points A, B, C, D, E and green points A, B, the coverage of the other transmitters is updated by removing those points.
ITERATION 2 Step 1: Analyze coverage Target coverage: Purple points F, G and green points C, D, E (5 units). Tx2 coverage: Purple point F and green points C, D (3 units). Tx3 coverage: Purple points F, G and green point E (3 units). Step 2: Score and choose the prioritized transmitter The scores for the green group will be multiplied by 2. There are no other factors that modify the score. P(Tx2) = 1/3 + 2/2*2 = 2.333 P(Tx3) = 2/3 + 1/2*2 = 1.667 Tx2 is chosen because it has the highest score. Step 3: Remove coverage provided by the chosen transmitter from the target coverage Remove the purple point F and the green points C, D that covered Tx2.
ITERATION 3 Step 1: Analyze coverage Target coverage: Purple point G and green point E (2 units). Tx3 coverage: Purple point G and green point E (2 units). Step 2: Score and choose the prioritized transmitter The scores for the green group will be multiplied by 2. There are no other factors that modify the score. P(Tx3) = 1/3 + 1/2*2 = 1.333 Tx3 is selected.
FINAL RESULT (SORTED BY SCORE) Tx2 covers 3 units and obtains a score of 2.333. Tx1 covers 7 units and obtains a score of 2.001. Tx3 covers 2 units and obtains a score of 1.333. |